9.1.7: Checkerboard V2 is a fundamental test of your ability to manipulate 2D lists (nested lists) using nested loops and conditional logic. While V1 typically focuses on simple row replacement, V2 requires a precise alternating pattern of 0s and 1s across the entire grid. Core Logic: The Alternating Pattern The primary challenge is ensuring that if a cell at (row, col) is a 1, the adjacent cells (up, down, left, right) are 0s. The Modulus Trick
: Create an 8x8 grid (a list of 8 lists, each containing 8 zeros). ): board.append([ Use code with caution. Copied to clipboard Nested Loop Iteration loops to visit every coordinate. Conditional Check : Use the modulus operator to determine which cells to flip. : board[r][c] = Use code with caution. Copied to clipboard Displaying the Result 9.1.7 Checkerboard V2 Codehs
: You are managing a list where each element is itself a list (representing a row). Logical Strategy To solve this correctly, follow these general steps: The Modulus Trick : Create an 8x8 grid
// Move to next line after each row System.out.println(); Conditional Check : Use the modulus operator to